Yak Aptitude : Pct Problems Amongst Explanations - Introduction

Hi friends, give thank you lot you thence much for the non bad reply to my yesterday's ship service on Partnership problems. Today I am posting the introduction together with problems on Percentage. In this ship service i am roofing the basic details of percentage, from our adjacent ship service nosotros shall encompass the problems alongside Higher difficulty level. Happy Reading :)

Percentage Problems Introduction

A fraction alongside denominator 100 is called percentage. Numerator of that fraction is called charge per unit of measurement percent.

The term percent agency per every 100.

fifty percent agency fifty out of 100.

The symbol % is used to announce percent.

Ex : 20%, 35%, 80% etc.

Percent to fraction : To convert percent into fraction, dissever the percent yesteryear 100.

Ex : 25% = 25/100 = 1/4

Fraction to percent : To convert fraction into percent, multiply the fraction yesteryear 100. 

Ex : 1/5 = (1/5) x 100 = 20%

Increment Percent = (Increment/Source) x 100

Ex : Increment % inward five together with three is (3/5) x 100  = 60%

Decrement Percent = (Decrement/Source) x 100

Ex : Decrement % inward five together with 8 is (5/8) x 100 = 37.5%

Some of import Percent / Fractions

100% = 1

50% = 1/2

25% = 1/4

20% = 1/5

40% = 2/5

60% = 3/5

16 2/3% = 1/6

33 1/3% = 1/3

66 2/3% = 2/3

12.5% = 1/8

6.25% = 1/16

75% = 3/4

80% = 4/5

10% = 1/10

125% = 5/4

37 1/2% = 3/8

87 1/2% = 7/8

Following rules should last kept inward take away heed for solving the questions on percentage

1. For converting a given per centum into a fraction, dissever it yesteryear 100 or multiply yesteryear 1/100.
2. For converting a given fraction into a per centum multiply it yesteryear 100.
3. For converting 1 given quantity, say, x equally a per centum of to a greater extent than or less other given quantity nation y, find (x/y) x 100 
• Note : Percentage is never expressed inward whatsoever unit of measurement similar rupees or kilos. 
4. When at that topographic point are 2 articles 'a' together with 'b' inward a grouping together with inward the ratio of a : b  then to limited whatsoever 1 article equally a per centum of the group, dissever the article yesteryear the full articles of the grouping together with multiply the whole yesteryear 100.

Now let's run into to a greater extent than or less basic Examples :

Example1 : Express 15% equally a fraction

Solution : 

15% = 15/100 or 3/20

Example 2 : Express 1/5 equally a percentage

Solution :

1/5 x 100 = twenty i.e. 20%

Example 3 : Find out 20% out of Rs. 650

Solution :

equally nosotros know, 20% = 20/100

Example 4 : How many percent is xv cm of 1 metre ?

Solution : 

Note : Both quantities are covered into same unit.

Example 5 : Influenza A virus subtype H5N1 someone spent 85% of his monthly income together with thereafter saves Rs. 360 per month. Find out his full income. 

Solution :

Suppose his monthly income is Rs. 100

Expenditure = 85% = Rs. 85

Saving = Rs. 100 - 85 = Rs. 15

If saving is Rs. xv , together with then income is Rs. 100

If saving is Rs. 360, together with then the income is =  (100 x 360) / 15  = Rs. 2400

Example 6 : If a pupil gets 38 marks out of 50, what is the per centum of his obtained marks ?

Solution : 

Percentage of obtained marks = (38/50) x 100  = 76%

Example 7 : If 2 numbers are respectively 30% together with 40% to a greater extent than than a 3rd number, what per centum is the kickoff of the mo ?

Solution :

Let the 3rd publish last 100

First publish = 100 + 30% of 100  = 130

together with Second publish = 100 + 40% of 100  = 140

=> Percentage of the kickoff publish to the mo publish to the mo number  = (130 x 100) / 140

 = 92.85

Example 8 : Influenza A virus subtype H5N1 pupil scores 20% marks together with fails yesteryear xxx marks spell to a greater extent than or less other pupil who scores 32% marks, gets 42 marks to a greater extent than than the minimum required boot the bucket marks. What are the maximum marks for the exam ?

Solution :

Example 9 : An applied scientific discipline pupil has to secure 50% marks to pass. He gets 163 marks together with fails yesteryear 37 marks. Find the maximum marks. 

Solution : 

Minimum marks required = 163 + 37  = 200

If fifty are the minimum marks together with then maximum marks  = 100

=>  twenty are the minimum marks, together with then maximum marks  =  (100 x 200) / 50  = 400

shared yesteryear Aindree Mukherjee

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